Resolucion:
La respuesta es la c). Uno de los fenomenos que se puede dar en el caldeo por induccion es el efecto pelicular. El material es sometido a un flujo magnetico variable. El calentamiento depende de la frecuencia de trabajo. La principal causa de calentamiento son las corrientes de Foucault
‹ Cuestion 1 S.POTENCIA 2012 09 S2 (Cicloconvertidor)arribaParte practica S.POTENCIA 2012 09 S2 (Bobina nucleo magnetico) ›
‹ Cuestion 1 S.POTENCIA 2012 09 S2 (Cicloconvertidor)arribaParte practica S.POTENCIA 2012 09 S2 (Bobina nucleo magnetico) ›
![[tex]R=R_1\cdot+R_2\cdot (\frac{N_1}{N_2})^2=[/tex] [tex]=4.5\cdot+4.5\cdot (1)^2=9\,\Omega[/tex]](http://1.bp.blogspot.com/-ATSt3yq5YNg/XYehH9aY_TI/AAAAAAAAGf8/-GTgrUlndbEpuUwitHsAbd8H6PgATmAawCK4BGAYYCw/s1600/formula9.JPG "[tex]R=R_1\cdot+R_2\cdot (\frac{N_1}{N_2})^2=[/tex] [tex]=4.5\cdot+4.5\cdot (1)^2=9\,\Omega[/tex]")
![[tex]L=L_{d1}\cdot+L_{d2}\cdot (\frac{N_1}{N_2})^2=[/tex]](http://3.bp.blogspot.com/-VT3W8JkYfZk/XYehQhNnEMI/AAAAAAAAGgE/Uaw2xEPr63s_fZTQWZ27Rw0smqrLZkrowCK4BGAYYCw/s1600/formula10.JPG "[tex]L=L_{d1}\cdot+L_{d2}\cdot (\frac{N_1}{N_2})^2=[/tex]")
![[tex]=5\cdot 10^{-6}\cdot+5\cdot 10^{-6}\cdot (1)^2=10\,\mu H[/tex]](http://4.bp.blogspot.com/-ciyEu3f4Y0Q/XYehZ5EDKZI/AAAAAAAAGgM/lSFQgEAoYVcAX5jLxBg_lu9-ECX33DcPACK4BGAYYCw/s1600/formula11.JPG "[tex]=5\cdot 10^{-6}\cdot+5\cdot 10^{-6}\cdot (1)^2=10\,\mu H[/tex]")
![[tex]C=C_{1}\cdot+C_{2}\cdot (\frac{N_2}{N_1})^2+\frac{C_a}{3}\cdot (1+\frac{N_2}{N_1}+(\frac{N_2}{N_1})^2)=[/tex] [tex]=1.2\cdot 10^{-9}\cdot+1.2\cdot 10^{-9}\cdot (1)^2+\frac{0.1\cdot 10^{-9}}{3}\cdot (1+1+(1)^2)=2.5\cdot 10^{-9}\, F[/tex]](http://2.bp.blogspot.com/-8k5k9r-5TZM/XYehj7uB1RI/AAAAAAAAGgY/YeMU1OttFiogGWwMLttrtP2X_5lB8ZaiQCK4BGAYYCw/s1600/formula12.JPG "[tex]C=C_{1}\cdot+C_{2}\cdot (\frac{N_2}{N_1})^2+\frac{C_a}{3}\cdot (1+\frac{N_2}{N_1}+(\frac{N_2}{N_1})^2)=[/tex] [tex]=1.2\cdot 10^{-9}\cdot+1.2\cdot 10^{-9}\cdot (1)^2+\frac{0.1\cdot 10^{-9}}{3}\cdot (1+1+(1)^2)=2.5\cdot 10^{-9}\, F[/tex]")
![[tex]R=R_1\cdot+R_2\cdot (\frac{N_1}{N_2})^2=[/tex] [tex]=4.5\cdot+4.5\cdot (1)^2=9\,\Omega[/tex]](http://3.bp.blogspot.com/-t_jCLKdt6Mk/XYeexFSdFXI/AAAAAAAAGfY/IDXDAxI8le8GnXm0UHDsNrwwpvcgCdZ_ACK4BGAYYCw/s1600/formula6.JPG "[tex]R=R_1\cdot+R_2\cdot (\frac{N_1}{N_2})^2=[/tex] [tex]=4.5\cdot+4.5\cdot (1)^2=9\,\Omega[/tex]")
![[tex]L_{mg}=10\,mH[/tex]](http://1.bp.blogspot.com/-vTdMNssVEv8/XYee6CBP-yI/AAAAAAAAGfg/v_H-5jGSobwS8KBvcQuXB9XSvRRxteP9QCK4BGAYYCw/s1600/formula7.JPG "[tex]L_{mg}=10\,mH[/tex]")
![[tex]R_{p1}=1\,K \Omega[/tex]](http://2.bp.blogspot.com/-eGnjIyQPrkI/XYefAY8P_4I/AAAAAAAAGfo/aoRavGOsYsUVdvUuLyrlow4ZoXPiboLBwCK4BGAYYCw/s1600/formula8.JPG "[tex]R_{p1}=1\,K \Omega[/tex]")
![[tex]C'=C_c+C=10\cdot 10^{-9}+2.5\cdot 10^{-9}[/tex][tex]=12.5\cdot 10^{-9} \,F[/tex]](http://3.bp.blogspot.com/-GHa014WrfWE/XYd--MzVLlI/AAAAAAAAGfM/go0QB3E2tZYu5An_kO5WEL2tyJ4QkWzbACK4BGAYYCw/s1600/formula4.JPG "[tex]C'=C_c+C=10\cdot 10^{-9}+2.5\cdot 10^{-9}[/tex][tex]=12.5\cdot 10^{-9} \,F[/tex]")
![[tex]a=\frac{R'}{R+R'}=[/tex] [tex]=\frac{107.14}{9+107.14}=0.9 \,Omega[/tex]](http://2.bp.blogspot.com/-BIP2NEpsYcY/XYagAuP3z4I/AAAAAAAAGeg/UrmZcEovqlwTfa3tKh6X2DyCPuV8haQwgCK4BGAYYCw/s1600/formula1.JPG "[tex]a=\frac{R'}{R+R'}=[/tex] [tex]=\frac{107.14}{9+107.14}=0.9 \,Omega[/tex]")
![[tex]T=2\cdot \pi \cdot \sqrt{L\cdot C'\cdot a}=2\cdot \pi \cdot \sqrt{10\cdot 10^{-3}\cdot 12.5\cdot 10^{-9}\cdot 0.9}=2.07\cdot 10^{-6}[/tex]](http://1.bp.blogspot.com/-BkbF2y9MVXw/XYagJ1JJ_4I/AAAAAAAAGeo/-ZvQHv5aJRMiLhCv_Ut-KwIm58f6cmpagCK4BGAYYCw/s1600/formula2.JPG "[tex]T=2\cdot \pi \cdot \sqrt{L\cdot C'\cdot a}=2\cdot \pi \cdot \sqrt{10\cdot 10^{-3}\cdot 12.5\cdot 10^{-9}\cdot 0.9}=2.07\cdot 10^{-6}[/tex]")
