Resolucion:
La respuesta es la c). Uno de los fenomenos que se puede dar en el caldeo por induccion es el efecto pelicular. El material es sometido a un flujo magnetico variable. El calentamiento depende de la frecuencia de trabajo. La principal causa de calentamiento son las corrientes de Foucault
‹ Cuestion 1 S.POTENCIA 2012 09 S2 (Cicloconvertidor)arribaParte practica S.POTENCIA 2012 09 S2 (Bobina nucleo magnetico) ›
‹ Cuestion 1 S.POTENCIA 2012 09 S2 (Cicloconvertidor)arribaParte practica S.POTENCIA 2012 09 S2 (Bobina nucleo magnetico) ›
![[tex]R=R_1\cdot+R_2\cdot (\frac{N_1}{N_2})^2=[/tex] [tex]=4.5\cdot+4.5\cdot (1)^2=9\,\Omega[/tex]](https://blogger.googleusercontent.com/img/b/R29vZ2xl/AVvXsEj2exjR-rR-CCEl3AIkE-oNWa2g7t-7v2c5lDthIH-g5XQZr53HndrykfZUiRCpmTK-Uaw8m23rvSj4u2wToVakE7nwuUPHhKnt6tAOFjAw_dg3DcRTaZ_rHM7cwyLim56PRQ8j-vB3GSQ8/s1600/formula9.JPG "[tex]R=R_1\cdot+R_2\cdot (\frac{N_1}{N_2})^2=[/tex] [tex]=4.5\cdot+4.5\cdot (1)^2=9\,\Omega[/tex]")
![[tex]L=L_{d1}\cdot+L_{d2}\cdot (\frac{N_1}{N_2})^2=[/tex]](https://blogger.googleusercontent.com/img/b/R29vZ2xl/AVvXsEjciVUzbP0L4xGeVjXEw3qOijoECKFsrwAf1zWW38RUPzNsqRHR8kGXw1e9Qq5kD5QBBwK6-uciLE26mwQhZnpklqpmFVLX5zp_VayxHl8TRO0t8BVuPks_be74b1-BLJQfAvaE1ql2eaiw/s1600/formula10.JPG "[tex]L=L_{d1}\cdot+L_{d2}\cdot (\frac{N_1}{N_2})^2=[/tex]")
![[tex]=5\cdot 10^{-6}\cdot+5\cdot 10^{-6}\cdot (1)^2=10\,\mu H[/tex]](https://blogger.googleusercontent.com/img/b/R29vZ2xl/AVvXsEiPSgw6CZsF6xwLdmx2sKRfHOUEkjT7_Jk3EWKGoL7RzdfmEEK1TexgTHAvLmcSohbhFq02SWuKqN4PZUITN85_WB3IrGSw7-xiHIiCFDboxFe4q8NOflrUh4chYLWb_ybmI5hmNMsKwdzX/s1600/formula11.JPG "[tex]=5\cdot 10^{-6}\cdot+5\cdot 10^{-6}\cdot (1)^2=10\,\mu H[/tex]")
![[tex]C=C_{1}\cdot+C_{2}\cdot (\frac{N_2}{N_1})^2+\frac{C_a}{3}\cdot (1+\frac{N_2}{N_1}+(\frac{N_2}{N_1})^2)=[/tex] [tex]=1.2\cdot 10^{-9}\cdot+1.2\cdot 10^{-9}\cdot (1)^2+\frac{0.1\cdot 10^{-9}}{3}\cdot (1+1+(1)^2)=2.5\cdot 10^{-9}\, F[/tex]](https://blogger.googleusercontent.com/img/b/R29vZ2xl/AVvXsEi3WoHSIrFYtRTb9RMi4JjfCAo3DU3I9mT9419zevGx-i7wQ2viXdZjIx426gp8DBQlq3F_3yeCbhT4nK6gxNnr888Cg05C5Ci5Yeje4MHfSw2gM-50SyXjINXiMrvXgAER8Q0ec2XD66SJ/s1600/formula12.JPG "[tex]C=C_{1}\cdot+C_{2}\cdot (\frac{N_2}{N_1})^2+\frac{C_a}{3}\cdot (1+\frac{N_2}{N_1}+(\frac{N_2}{N_1})^2)=[/tex] [tex]=1.2\cdot 10^{-9}\cdot+1.2\cdot 10^{-9}\cdot (1)^2+\frac{0.1\cdot 10^{-9}}{3}\cdot (1+1+(1)^2)=2.5\cdot 10^{-9}\, F[/tex]")
![[tex]R=R_1\cdot+R_2\cdot (\frac{N_1}{N_2})^2=[/tex] [tex]=4.5\cdot+4.5\cdot (1)^2=9\,\Omega[/tex]](https://blogger.googleusercontent.com/img/b/R29vZ2xl/AVvXsEjJXkLY5Li-qA53d2RyV9ADSlm9lDzL7lbesE9uMqqyxz5KacyC1JSRSdrA_lH1NEiPbH7_W9GNTEaVBgq-e365vVp_7MgwlysQ4mo17e5fCkSeCUUZBYmBFZ8LlDRoJIYRLUXa3CPZKogT/s1600/formula6.JPG "[tex]R=R_1\cdot+R_2\cdot (\frac{N_1}{N_2})^2=[/tex] [tex]=4.5\cdot+4.5\cdot (1)^2=9\,\Omega[/tex]")
![[tex]L_{mg}=10\,mH[/tex]](https://blogger.googleusercontent.com/img/b/R29vZ2xl/AVvXsEjeJxeLmuV-kQvG_JhgVVnD41tpiqlQDeYNA2im08rtsd7uJZdA8Qc6tFTzHTRPQUDs_YETxVErLYxYJqkZKV_qpUkyO_GRf1LPnqvKdikxOLMYl-OzxKd9QsBw8JemFwENukY2JRe2UM30/s1600/formula7.JPG "[tex]L_{mg}=10\,mH[/tex]")
![[tex]R_{p1}=1\,K \Omega[/tex]](https://blogger.googleusercontent.com/img/b/R29vZ2xl/AVvXsEiEHLsylERkT_qX-0b6SgQJPCcrotde4JowMNcwLb-z_0DhHgH3kx7ZaExhC03IcoP0V-ySgLqJzLOZaC7muC2lz6BP9AIsVbEGnZhMvF79GcXTahFp1s0zKO-CuEDlJ6EPPn96RxucYEc7/s1600/formula8.JPG "[tex]R_{p1}=1\,K \Omega[/tex]")
![[tex]C'=C_c+C=10\cdot 10^{-9}+2.5\cdot 10^{-9}[/tex][tex]=12.5\cdot 10^{-9} \,F[/tex]](https://blogger.googleusercontent.com/img/b/R29vZ2xl/AVvXsEglWx7eWOb8eVoUb0nfsawx_6437vmF_HsZ574GgyL0CpQbB06r7__iuxZcnYf5HRn0WkN6GXjmwqA4LglpC1MAtlRhPynFVZ4WBxCnNxY20gol8bzxdh_ArghFseJZMD25_nU8uU5bZ8e1/s1600/formula4.JPG "[tex]C'=C_c+C=10\cdot 10^{-9}+2.5\cdot 10^{-9}[/tex][tex]=12.5\cdot 10^{-9} \,F[/tex]")
![[tex]a=\frac{R'}{R+R'}=[/tex] [tex]=\frac{107.14}{9+107.14}=0.9 \,Omega[/tex]](https://blogger.googleusercontent.com/img/b/R29vZ2xl/AVvXsEiyojLMlCappt1uup_4BCo7RKD1HgN_E9SYC_XlBT2k64ozX5_SKzKkXmrM7cR8eTc6CpFWGsCLUG1lIwJxNTBCzA13obRnYKBw4Eh-AwAhJrBJ25MkZCndXdNJfv9wx-dw0JJqkI1OPi1d/s1600/formula1.JPG "[tex]a=\frac{R'}{R+R'}=[/tex] [tex]=\frac{107.14}{9+107.14}=0.9 \,Omega[/tex]")
![[tex]T=2\cdot \pi \cdot \sqrt{L\cdot C'\cdot a}=2\cdot \pi \cdot \sqrt{10\cdot 10^{-3}\cdot 12.5\cdot 10^{-9}\cdot 0.9}=2.07\cdot 10^{-6}[/tex]](https://blogger.googleusercontent.com/img/b/R29vZ2xl/AVvXsEiOzBrzn33kq7VLlOdZFIBBnFpIdCVJR2ipVqMNqk8MrsRrahiz_913tWF19sXvwhfJGt44cNRDEzeoMEgxC9RwGmjcqEOfh4nuNoyFT7UyVgXkB5EOfi6ySThewKQXdKwMShAf53CSCtLj/s1600/formula2.JPG "[tex]T=2\cdot \pi \cdot \sqrt{L\cdot C'\cdot a}=2\cdot \pi \cdot \sqrt{10\cdot 10^{-3}\cdot 12.5\cdot 10^{-9}\cdot 0.9}=2.07\cdot 10^{-6}[/tex]")
